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(81n^2)-9=7
We move all terms to the left:
(81n^2)-9-(7)=0
We add all the numbers together, and all the variables
81n^2-16=0
a = 81; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·81·(-16)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*81}=\frac{-72}{162} =-4/9 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*81}=\frac{72}{162} =4/9 $
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